S∞ = a₁/(1−r), |r|<1z = (x−μ)/σ∑ₙ₌₁^∞ 1/n² = π²/6(a+b)(a−b) = a²−b²a/sin A = b/sin Blogₐ(xy) = logₐx + logₐyP(A|B) = P(A∩B)/P(B)x = (−b±√(b²−4ac))/2aV = ⁴⁄₃πr³y = a(x−h)² + kx² + y² = r²a/sin A = b/sin BA = πr²d/dx[f(g(x))] = f′(g(x))·g′(x)Sₙ = n/2(a₁+aₙ)y = Aeᵏˣd/dx[f/g] = (f′g−fg′)/g²nCr = n!/(r!(n−r)!)d/dx[eˣ] = eˣS∞ = a₁/(1−r), |r|<1logₐ(xy) = logₐx + logₐyy = mx + blim(x→0) sinx/x = 1lim(x→∞)(1+1/x)ˣ = ea/sin A = b/sin Btan θ = sin θ/cos θS∞ = a₁/(1−r), |r|<1z = (x−μ)/σaₙ = a₁·rⁿ⁻¹V = ⁴⁄₃πr³∫1/x dx = ln|x| + Cz = (x−μ)/σd/dx[f·g] = f′g + fg′(a+b)² = a²+2ab+b²lim(x→∞)(1+1/x)ˣ = e1 + tan²θ = sec²θ(a+b)(a−b) = a²−b²x² + y² = r²S∞ = a₁/(1−r), |r|<1c² = a²+b²−2ab cosCtan θ = sin θ/cos θy = Aeᵏˣc² = a²+b²−2ab cosClim(x→∞)(1+1/x)ˣ = ea² + b² = c²C = 2πrlogₐ(xy) = logₐx + logₐy∫ₐᵇ f(x) dx = F(b)−F(a)lim(x→∞)(1+1/x)ˣ = e∫1/x dx = ln|x| + Caₙ = a₁·rⁿ⁻¹(a+b)(a−b) = a²−b²V = ⁴⁄₃πr³a² + b² = c²nPr = n!/(n−r)!d/dx[eˣ] = eˣlim(x→0) sinx/x = 1m = (y₂−y₁)/(x₂−x₁)S∞ = a₁/(1−r), |r|<1x = (−b±√(b²−4ac))/2atan θ = sin θ/cos θx = (−b±√(b²−4ac))/2aC = 2πrd/dx[eˣ] = eˣnCr = n!/(r!(n−r)!)d/dx[sin x] = cos xS∞ = a₁/(1−r), |r|<1x̄ = Σxᵢ/nA = πr²x̄ = Σxᵢ/nx = (−b±√(b²−4ac))/2a∫1/x dx = ln|x| + Ccos(2θ) = cos²θ − sin²θtan θ = sin θ/cos θnCr = n!/(r!(n−r)!)∫ₐᵇ f(x) dx = F(b)−F(a)d/dx[cos x] = −sin xd/dx[f(g(x))] = f′(g(x))·g′(x)∫xⁿ dx = xⁿ⁺¹/(n+1) + CnCr = n!/(r!(n−r)!)∫sin x dx = −cos x + C∑ₙ₌₁^∞ 1/n² = π²/6P(A∪B) = P(A)+P(B)−P(A∩B)d/dx[eˣ] = eˣlogₐ(xⁿ) = n logₐxx² + y² = r²nPr = n!/(n−r)!a² + b² = c²d/dx[f(g(x))] = f′(g(x))·g′(x)d/dx[sin x] = cos xd/dx[ln x] = 1/xV = ⁴⁄₃πr³y = a(x−h)² + kcos(2θ) = cos²θ − sin²θd = √((x₂−x₁)²+(y₂−y₁)²)logₐ(xⁿ) = n logₐxd/dx[eˣ] = eˣ∫ₐᵇ f(x) dx = F(b)−F(a)a² + b² = c²∫ₐᵇ f(x) dx = F(b)−F(a)∫cos x dx = sin x + Csin(A+B) = sinA cosB + cosA sinBΔ = b²−4acP(A∪B) = P(A)+P(B)−P(A∩B)(a+b)(a−b) = a²−b²Δ = b²−4acx̄ = Σxᵢ/ntan θ = sin θ/cos θtan θ = sin θ/cos θlogₐ(x/y) = logₐx − logₐyd/dx[xⁿ] = nxⁿ⁻¹Δ = b²−4ac∑ᵢ₌₁ⁿ i = n(n+1)/2z = (x−μ)/σd/dx[f/g] = (f′g−fg′)/g²d/dx[xⁿ] = nxⁿ⁻¹sin²θ + cos²θ = 1sin²θ + cos²θ = 1∑ᵢ₌₁ⁿ i = n(n+1)/2sin(2θ) = 2 sinθ cosθx² + y² = r²A = πr²cos(2θ) = cos²θ − sin²θe^(iπ) + 1 = 0P(A|B) = P(A∩B)/P(B)∫1/x dx = ln|x| + Cd = √((x₂−x₁)²+(y₂−y₁)²)Sₙ = n/2(a₁+aₙ)S∞ = a₁/(1−r), |r|<1d/dx[cos x] = −sin xlogₐ(xy) = logₐx + logₐy∫1/x dx = ln|x| + Cm = (y₂−y₁)/(x₂−x₁)∑ᵢ₌₁ⁿ i = n(n+1)/2d/dx[ln x] = 1/xc² = a²+b²−2ab cosCcos(2θ) = cos²θ − sin²θSₙ = n/2(a₁+aₙ)aₙ = a₁·rⁿ⁻¹cos(2θ) = cos²θ − sin²θ∫ₐᵇ f(x) dx = F(b)−F(a)logₐ(x/y) = logₐx − logₐyΔ = b²−4ac∫sin x dx = −cos x + Cd = √((x₂−x₁)²+(y₂−y₁)²)x² + y² = r²x̄ = Σxᵢ/nd/dx[sin x] = cos xsin²θ + cos²θ = 1∑ᵢ₌₁ⁿ i² = n(n+1)(2n+1)/6f′(x) = lim(h→0)[f(x+h)−f(x)]/he^(iπ) + 1 = 0d/dx[f(g(x))] = f′(g(x))·g′(x)y = AeᵏˣSₙ = n/2(a₁+aₙ)aₙ = a₁·rⁿ⁻¹(a+b)² = a²+2ab+b²C = 2πrP(A∪B) = P(A)+P(B)−P(A∩B)aₙ = a₁ + (n−1)dlim(x→∞)(1+1/x)ˣ = elim(x→∞)(1+1/x)ˣ = eC = 2πrP(A|B) = P(A∩B)/P(B)y = Aeᵏˣaₙ = a₁ + (n−1)d∑ᵢ₌₁ⁿ i = n(n+1)/2d/dx[f/g] = (f′g−fg′)/g²x̄ = Σxᵢ/nlim(x→∞)(1+1/x)ˣ = e∑ₙ₌₁^∞ 1/n² = π²/6x = (−b±√(b²−4ac))/2a∫sin x dx = −cos x + Ca² + b² = c²(a+b)(a−b) = a²−b²logₐx = ln x/ln af′(x) = lim(h→0)[f(x+h)−f(x)]/h∫ₐᵇ f(x) dx = F(b)−F(a)d/dx[cos x] = −sin x(a+b)(a−b) = a²−b²∑ᵢ₌₁ⁿ i = n(n+1)/2tan θ = sin θ/cos θA = πr²d/dx[f(g(x))] = f′(g(x))·g′(x)∑ᵢ₌₁ⁿ i = n(n+1)/2d/dx[eˣ] = eˣsin(2θ) = 2 sinθ cosθx = (−b±√(b²−4ac))/2am = (y₂−y₁)/(x₂−x₁)(a+b)(a−b) = a²−b²S∞ = a₁/(1−r), |r|<1c² = a²+b²−2ab cosCP(A|B) = P(A∩B)/P(B)d/dx[xⁿ] = nxⁿ⁻¹sin²θ + cos²θ = 1logₐx = ln x/ln ac² = a²+b²−2ab cosCnPr = n!/(n−r)!z = (x−μ)/σV = ⁴⁄₃πr³P(A|B) = P(A∩B)/P(B)∑ₙ₌₁^∞ 1/n² = π²/6sin(A+B) = sinA cosB + cosA sinBx̄ = Σxᵢ/n∑ᵢ₌₁ⁿ i² = n(n+1)(2n+1)/6y = mx + bd/dx[sin x] = cos xx² + y² = r²d/dx[f(g(x))] = f′(g(x))·g′(x)f′(x) = lim(h→0)[f(x+h)−f(x)]/hz = (x−μ)/σlim(x→∞)(1+1/x)ˣ = ed/dx[cos x] = −sin xx = (−b±√(b²−4ac))/2ax² + y² = r²cos(2θ) = cos²θ − sin²θd/dx[cos x] = −sin xlogₐ(xⁿ) = n logₐxsin²θ + cos²θ = 1∫cos x dx = sin x + Cy = a(x−h)² + kC = 2πraₙ = a₁ + (n−1)dP(A∪B) = P(A)+P(B)−P(A∩B)x² + y² = r²logₐ(xy) = logₐx + logₐyaₙ = a₁ + (n−1)daₙ = a₁·rⁿ⁻¹nPr = n!/(n−r)!(a+b)(a−b) = a²−b²nCr = n!/(r!(n−r)!)∫1/x dx = ln|x| + Cm = (y₂−y₁)/(x₂−x₁)∫ₐᵇ f(x) dx = F(b)−F(a)m = (y₂−y₁)/(x₂−x₁)d/dx[eˣ] = eˣ∫cos x dx = sin x + C∑ᵢ₌₁ⁿ i = n(n+1)/2d/dx[ln x] = 1/xlogₐ(x/y) = logₐx − logₐyx̄ = Σxᵢ/ny = mx + b∫ₐᵇ f(x) dx = F(b)−F(a)lim(x→∞)(1+1/x)ˣ = ex² + y² = r²x̄ = Σxᵢ/nlogₐ(xⁿ) = n logₐxV = ⁴⁄₃πr³lim(x→∞)(1+1/x)ˣ = esin(A+B) = sinA cosB + cosA sinBsin²θ + cos²θ = 1(a+b)² = a²+2ab+b²lim(x→∞)(1+1/x)ˣ = ec² = a²+b²−2ab cosCy = Aeᵏˣ(a+b)(a−b) = a²−b²sin(A+B) = sinA cosB + cosA sinBlim(x→0) sinx/x = 1d/dx[ln x] = 1/x1 + tan²θ = sec²θd/dx[cos x] = −sin xS∞ = a₁/(1−r), |r|<1d/dx[eˣ] = eˣtan θ = sin θ/cos θz = (x−μ)/σd/dx[eˣ] = eˣnCr = n!/(r!(n−r)!)sin(A+B) = sinA cosB + cosA sinBSₙ = n/2(a₁+aₙ)sin(A+B) = sinA cosB + cosA sinBP(A|B) = P(A∩B)/P(B)d/dx[eˣ] = eˣ∑ᵢ₌₁ⁿ i² = n(n+1)(2n+1)/6(a+b)(a−b) = a²−b²x = (−b±√(b²−4ac))/2a∫cos x dx = sin x + C∫sin x dx = −cos x + Clogₐx = ln x/ln af′(x) = lim(h→0)[f(x+h)−f(x)]/hd/dx[ln x] = 1/x∑ₙ₌₁^∞ 1/n² = π²/6f′(x) = lim(h→0)[f(x+h)−f(x)]/hd/dx[cos x] = −sin xd/dx[xⁿ] = nxⁿ⁻¹sin(2θ) = 2 sinθ cosθ∫xⁿ dx = xⁿ⁺¹/(n+1) + Ce^(iπ) + 1 = 0∑ᵢ₌₁ⁿ i = n(n+1)/2(a+b)(a−b) = a²−b²C = 2πr∫xⁿ dx = xⁿ⁺¹/(n+1) + Cy = mx + baₙ = a₁·rⁿ⁻¹d/dx[f/g] = (f′g−fg′)/g²lim(x→∞)(1+1/x)ˣ = elim(x→∞)(1+1/x)ˣ = ey = mx + ba² + b² = c²x̄ = Σxᵢ/nsin(2θ) = 2 sinθ cosθΔ = b²−4aclogₐx = ln x/ln a∫eˣ dx = eˣ + C∫sin x dx = −cos x + Cf′(x) = lim(h→0)[f(x+h)−f(x)]/hd/dx[f(g(x))] = f′(g(x))·g′(x)m = (y₂−y₁)/(x₂−x₁)nPr = n!/(n−r)!P(A∪B) = P(A)+P(B)−P(A∩B)∫cos x dx = sin x + Cd/dx[cos x] = −sin xA = πr²∫xⁿ dx = xⁿ⁺¹/(n+1) + Cz = (x−μ)/σd/dx[sin x] = cos xd = √((x₂−x₁)²+(y₂−y₁)²)sin(2θ) = 2 sinθ cosθC = 2πrC = 2πrlim(x→∞)(1+1/x)ˣ = ee^(iπ) + 1 = 0nCr = n!/(r!(n−r)!)f′(x) = lim(h→0)[f(x+h)−f(x)]/ha² + b² = c²sin²θ + cos²θ = 1lim(x→0) sinx/x = 1aₙ = a₁·rⁿ⁻¹1 + tan²θ = sec²θd/dx[cos x] = −sin x∫cos x dx = sin x + Csin²θ + cos²θ = 1∑ᵢ₌₁ⁿ i = n(n+1)/2nCr = n!/(r!(n−r)!)f′(x) = lim(h→0)[f(x+h)−f(x)]/h∫1/x dx = ln|x| + C∑ₙ₌₁^∞ 1/n² = π²/6nCr = n!/(r!(n−r)!)logₐ(xy) = logₐx + logₐya² + b² = c²f′(x) = lim(h→0)[f(x+h)−f(x)]/hz = (x−μ)/σ∫eˣ dx = eˣ + C∑ₙ₌₁^∞ 1/n² = π²/6cos(2θ) = cos²θ − sin²θe^(iπ) + 1 = 0c² = a²+b²−2ab cosClim(x→∞)(1+1/x)ˣ = ey = a(x−h)² + klogₐ(xⁿ) = n logₐx∫ₐᵇ f(x) dx = F(b)−F(a)
Math & Computer Studies · Senior High School
Rod Monk
BC Certified Teacher · BSc (Hons) · MEng
Teaching mathematics and computing with clarity, curiosity, and real-world relevance.